BigUInt
public struct BigUInt : UnsignedInteger
extension BigUInt: Comparable
extension BigUInt: Hashable
extension BigUInt: ExpressibleByIntegerLiteral
extension BigUInt: ExpressibleByStringLiteral
extension BigUInt: CustomPlaygroundDisplayConvertible
An arbitary precision unsigned integer type, also known as a “big integer”.
Operations on big integers never overflow, but they may take a long time to execute. The amount of memory (and address space) available is the only constraint to the magnitude of these numbers.
This particular big integer type uses base-2^64 digits to represent integers; you can think of it as a wrapper
around Array<UInt64>
. (In fact, BigUInt
only uses an array if there are more than two digits.)
-
The type representing a digit in
BigUInt
‘s underlying number system.Declaration
Swift
public typealias Word = UInt
-
Undocumented
Declaration
Swift
internal fileprivate(set) var kind: Kind { get }
-
Undocumented
Declaration
Swift
internal fileprivate(set) var storage: [Word] { get }
-
Initializes a new BigUInt with value 0.
Declaration
Swift
public init()
-
Undocumented
Declaration
Swift
internal init(word: Word)
-
Initializes a new BigUInt with the specified digits. The digits are ordered from least to most significant.
Declaration
Swift
public init(words: [Word])
-
Undocumented
Declaration
Swift
internal init(words: [Word], from startIndex: Int, to endIndex: Int)
-
Add
word
to this integer in place.word
is shiftedshift
words to the left before being added.Complexity
O(max(count, shift))Declaration
Swift
internal mutating func addWord(_ word: Word, shiftedBy shift: Int = 0)
-
Add the digit
d
to this integer and return the result.d
is shiftedshift
words to the left before being added.Complexity
O(max(count, shift))Declaration
Swift
internal func addingWord(_ word: Word, shiftedBy shift: Int = 0) -> BigUInt
-
Add
b
to this integer in place.b
is shiftedshift
words to the left before being added.Complexity
O(max(count, b.count + shift))Declaration
Swift
internal mutating func add(_ b: BigUInt, shiftedBy shift: Int = 0)
-
Add
b
to this integer and return the result.b
is shiftedshift
words to the left before being added.Complexity
O(max(count, b.count + shift))Declaration
Swift
internal func adding(_ b: BigUInt, shiftedBy shift: Int = 0) -> BigUInt
-
Increment this integer by one. If
shift
is non-zero, it selects the word that is to be incremented.Complexity
O(count + shift)Declaration
Swift
internal mutating func increment(shiftedBy shift: Int = 0)
-
Add
a
andb
together and return the result.Complexity
O(max(a.count, b.count))Declaration
Swift
public static func + (a: BigUInt, b: BigUInt) -> BigUInt
-
Add
a
andb
together, and store the sum ina
.Complexity
O(max(a.count, b.count))Declaration
Swift
public static func += (a: inout BigUInt, b: BigUInt)
-
Declaration
Swift
public static var isSigned: Bool { get }
-
Return true iff this integer is zero.
Complexity
O(1)Declaration
Swift
public var isZero: Bool { get }
-
Returns
1
if this value is, positive; otherwise,0
.Declaration
Swift
public func signum() -> BigUInt
Return Value
The sign of this number, expressed as an integer of the same type.
-
Undocumented
Declaration
Swift
mutating func ensureArray()
-
Undocumented
Declaration
Swift
var capacity: Int { get }
-
Undocumented
Declaration
Swift
mutating func reserveCapacity(_ minimumCapacity: Int)
-
Gets rid of leading zero digits in the digit array and converts slices into inline digits when possible.
Declaration
Swift
internal mutating func normalize()
-
Set this integer to 0 without releasing allocated storage capacity (if any).
Declaration
Swift
mutating func clear()
-
Set this integer to
value
by copying its digits without releasing allocated storage capacity (if any).Declaration
Swift
mutating func load(_ value: BigUInt)
-
The number of digits in this integer, excluding leading zero digits.
Declaration
Swift
var count: Int { get }
-
Get or set a digit at a given index.
Note
Unlike a normal collection, it is OK for the index to be greater than or equal toendIndex
. The subscripting getter returns zero for indexes beyond the most significant digit. Setting these extended digits automatically appends new elements to the underlying digit array.Requires
index >= 0Complexity
The getter is O(1). The setter is O(1) if the conditions below are true; otherwise it’s O(count).- The integer’s storage is not shared with another integer
- The integer wasn’t created as a slice of another integer
index < count
Declaration
Swift
subscript(index: Int) -> Word { get set }
-
Returns an integer built from the digits of this integer in the given range.
Declaration
Swift
internal func extract(_ bounds: Range<Int>) -> BigUInt
-
Undocumented
Declaration
Swift
internal func extract<Bounds>(_ bounds: Bounds) -> BigUInt where Bounds : RangeExpression, Bounds.Bound == Int
-
Undocumented
Declaration
Swift
internal mutating func shiftRight(byWords amount: Int)
-
Undocumented
Declaration
Swift
internal mutating func shiftLeft(byWords amount: Int)
-
Split this integer into a high-order and a low-order part.
Requires
count > 1Complexity
Typically O(1), but O(count) in the worst case, because high-order zero digits need to be removed after the split.Declaration
Swift
internal var split: (high: BigUInt, low: BigUInt) { get }
Return Value
(low, high)
such thatself == low.add(high, shiftedBy: middleIndex)
high.width <= floor(width / 2)
low.width <= ceil(width / 2)
-
Index of the digit at the middle of this integer.
Declaration
Swift
internal var middleIndex: Int { get }
Return Value
The index of the digit that is least significant in
self.high
. -
The low-order half of this BigUInt.
Requires
count > 1Declaration
Swift
internal var low: BigUInt { get }
Return Value
self[0 ..< middleIndex]
-
The high-order half of this BigUInt.
Requires
count > 1Declaration
Swift
internal var high: BigUInt { get }
Return Value
self[middleIndex ..< count]
-
Return the ones’ complement of
a
.Complexity
O(a.count)Declaration
Swift
public prefix static func ~ (a: BigUInt) -> BigUInt
-
Calculate the bitwise OR of
a
andb
, and store the result ina
.Complexity
O(max(a.count, b.count))Declaration
Swift
public static func |= (a: inout BigUInt, b: BigUInt)
-
Calculate the bitwise AND of
a
andb
and return the result.Complexity
O(max(a.count, b.count))Declaration
Swift
public static func &= (a: inout BigUInt, b: BigUInt)
-
Calculate the bitwise XOR of
a
andb
and return the result.Complexity
O(max(a.count, b.count))Declaration
Swift
public static func ^= (a: inout BigUInt, b: BigUInt)
-
Compare
a
tob
and return anNSComparisonResult
indicating their order.Complexity
O(count)Declaration
Swift
public static func compare(_ a: BigUInt, _ b: BigUInt) -> ComparisonResult
-
Return true iff
a
is equal tob
.Complexity
O(count)Declaration
Swift
public static func == (a: BigUInt, b: BigUInt) -> Bool
-
Return true iff
a
is less thanb
.Complexity
O(count)Declaration
Swift
public static func < (a: BigUInt, b: BigUInt) -> Bool
-
Initialize a BigInt from bytes accessed from an UnsafeRawBufferPointer
Declaration
Swift
public init(_ buffer: UnsafeRawBufferPointer)
-
Initializes an integer from the bits stored inside a piece of
Data
. The data is assumed to be in network (big-endian) byte order.Declaration
Swift
public init(_ data: Data)
-
Return a
Data
value that contains the base-256 representation of this integer, in network (big-endian) byte order.Declaration
Swift
public func serialize() -> Data
-
Divide this integer by the word
y
and return the resulting quotient and remainder.Requires
y > 0Complexity
O(x.count)Declaration
Return Value
(quotient, remainder) where quotient = floor(x/y), remainder = x - quotient * y
-
Divide
x
byy
, putting the quotient inx
and the remainder iny
. Reusing integers like this reduces the number of allocations during the calculation.Declaration
Swift
static func divide(_ x: inout BigUInt, by y: inout BigUInt)
-
Divide
x
byy
, putting the remainder inx
.Declaration
Swift
mutating func formRemainder(dividingBy y: BigUInt, normalizedBy shift: Int)
-
Divide this integer by
y
and return the resulting quotient and remainder.Requires
y > 0
Complexity
O(count^2)Declaration
Swift
public func quotientAndRemainder(dividingBy y: BigUInt) -> (quotient: BigUInt, remainder: BigUInt)
Return Value
(quotient, remainder)
wherequotient = floor(self/y)
,remainder = self - quotient * y
-
Divide
x
byy
and return the quotient.Note
Usedivided(by:)
if you also need the remainder.Declaration
Swift
public static func / (x: BigUInt, y: BigUInt) -> BigUInt
-
Divide
x
byy
and return the remainder.Note
Usedivided(by:)
if you also need the remainder.Declaration
Swift
public static func % (x: BigUInt, y: BigUInt) -> BigUInt
-
Divide
x
byy
and store the quotient inx
.Note
Usedivided(by:)
if you also need the remainder.Declaration
Swift
public static func /= (x: inout BigUInt, y: BigUInt)
-
Divide
x
byy
and store the remainder inx
.Note
Usedivided(by:)
if you also need the remainder.Declaration
Swift
public static func %= (x: inout BigUInt, y: BigUInt)
-
Returns this integer raised to the power
exponent
.This function calculates the result by successively squaring the base while halving the exponent.
Note
This function can be unreasonably expensive for large exponents, which is whyexponent
is a simple integer value. If you want to calculate big exponents, you’ll probably need to use the modulo arithmetic variant.See also
BigUInt.power(_:, modulus:)
Complexity
O((exponent * self.count)^log2(3)) or somesuch. The result may require a large amount of memory, too.Declaration
Swift
public func power(_ exponent: Int) -> BigUInt
Return Value
1 if
exponent == 0
, otherwiseself
raised toexponent
. (This implies that0.power(0) == 1
.) -
Returns the remainder of this integer raised to the power
exponent
in modulo arithmetic undermodulus
.Uses the right-to-left binary method.
Complexity
O(exponent.count * modulus.count^log2(3)) or somesuchDeclaration
Swift
public func power(_ exponent: BigUInt, modulus: BigUInt) -> BigUInt
-
Declaration
Swift
public init?<T>(exactly source: T) where T : BinaryFloatingPoint
-
Declaration
Swift
public init<T>(_ source: T) where T : BinaryFloatingPoint
-
Append this
BigUInt
to the specified hasher.Declaration
Swift
public func hash(into hasher: inout Hasher)
-
Declaration
Swift
public init?<T>(exactly source: T) where T : BinaryInteger
-
Declaration
Swift
public init<T>(_ source: T) where T : BinaryInteger
-
Declaration
Swift
public init<T>(truncatingIfNeeded source: T) where T : BinaryInteger
-
Declaration
Swift
public init<T>(clamping source: T) where T : BinaryInteger
-
Initialize a new big integer from an integer literal.
Declaration
Swift
public init(integerLiteral value: UInt64)
-
Multiply this big integer by a single word, and store the result in place of the original big integer.
Complexity
O(count)Declaration
Swift
public mutating func multiply(byWord y: Word)
-
Multiply this big integer by a single Word, and return the result.
Complexity
O(count)Declaration
Swift
public func multiplied(byWord y: Word) -> BigUInt
-
Multiply
x
byy
, and add the result to this integer, optionally shiftedshift
words to the left.Note
This is the fused multiply/shift/add operation; it is more efficient than doing the components individually. (The fused operation doesn’t need to allocate space for temporary big integers.)Complexity
O(count)Declaration
Swift
public mutating func multiplyAndAdd(_ x: BigUInt, _ y: Word, shiftedBy shift: Int = 0)
Return Value
self
is set toself + (x * y) << (shift * 2^Word.bitWidth)
-
Multiply this integer by
y
and return the result.Note
This uses the naive O(n^2) multiplication algorithm unless both arguments have more thanBigUInt.directMultiplicationLimit
words.Complexity
O(n^log2(3))Declaration
Swift
public func multiplied(by y: BigUInt) -> BigUInt
-
Multiplication switches to an asymptotically better recursive algorithm when arguments have more words than this limit.
Declaration
Swift
public static var directMultiplicationLimit: Int
-
Multiply
a
byb
and return the result.Note
This uses the naive O(n^2) multiplication algorithm unless both arguments have more thanBigUInt.directMultiplicationLimit
words.Complexity
O(n^log2(3))Declaration
Swift
public static func * (x: BigUInt, y: BigUInt) -> BigUInt
-
Multiply
a
byb
and store the result ina
.Declaration
Swift
public static func *= (a: inout BigUInt, b: BigUInt)
-
Undocumented
Declaration
Swift
internal func shiftedLeft(by amount: Word) -> BigUInt
-
Undocumented
Declaration
Swift
internal mutating func shiftLeft(by amount: Word)
-
Undocumented
Declaration
Swift
internal func shiftedRight(by amount: Word) -> BigUInt
-
Undocumented
Declaration
Swift
internal mutating func shiftRight(by amount: Word)
-
Undocumented
Declaration
Swift
public static func >>= <Other>(lhs: inout BigUInt, rhs: Other) where Other : BinaryInteger
-
Undocumented
Declaration
Swift
public static func <<= <Other>(lhs: inout BigUInt, rhs: Other) where Other : BinaryInteger
-
Undocumented
Declaration
Swift
public static func >> <Other>(lhs: BigUInt, rhs: Other) -> BigUInt where Other : BinaryInteger
-
Undocumented
Declaration
Swift
public static func << <Other>(lhs: BigUInt, rhs: Other) -> BigUInt where Other : BinaryInteger
-
Initialize a big integer from an ASCII representation in a given radix. Numerals above
9
are represented by letters from the English alphabet.Requires
radix > 1 && radix < 36
Declaration
Swift
public init?<S>(_ text: S, radix: Int = 10) where S : StringProtocol
Return Value
The integer represented by
text
, or nil iftext
contains a character that does not represent a numeral inradix
. -
Initialize a new big integer from a Unicode scalar. The scalar must represent a decimal digit.
Declaration
Swift
public init(unicodeScalarLiteral value: UnicodeScalar)
-
Initialize a new big integer from an extended grapheme cluster. The cluster must consist of a decimal digit.
Declaration
Swift
public init(extendedGraphemeClusterLiteral value: String)
-
Initialize a new big integer from a decimal number represented by a string literal of arbitrary length. The string must contain only decimal digits.
Declaration
Swift
public init(stringLiteral value: StringLiteralType)
-
Return the playground quick look representation of this integer.
Declaration
Swift
public var playgroundDescription: Any { get }
-
Subtract
word
from this integer in place, returning a flag indicating if the operation caused an arithmetic overflow.word
is shiftedshift
words to the left before being subtracted.Note
If the result indicates an overflow, thenself
becomes the two’s complement of the absolute difference.Complexity
O(count)Declaration
Swift
internal mutating func subtractWordReportingOverflow(_ word: Word, shiftedBy shift: Int = 0) -> Bool
-
Subtract
word
from this integer, returning the difference and a flag that is true if the operation caused an arithmetic overflow.word
is shiftedshift
words to the left before being subtracted.Note
Ifoverflow
is true, then the returned value is the two’s complement of the absolute difference.Complexity
O(count)Declaration
Swift
internal func subtractingWordReportingOverflow(_ word: Word, shiftedBy shift: Int = 0) -> (partialValue: BigUInt, overflow: Bool)
-
Subtract a digit
d
from this integer in place.d
is shiftedshift
digits to the left before being subtracted.Requires
self >= d * 2^shiftComplexity
O(count)Declaration
Swift
internal mutating func subtractWord(_ word: Word, shiftedBy shift: Int = 0)
-
Subtract a digit
d
from this integer and return the result.d
is shiftedshift
digits to the left before being subtracted.Requires
self >= d * 2^shiftComplexity
O(count)Declaration
Swift
internal func subtractingWord(_ word: Word, shiftedBy shift: Int = 0) -> BigUInt
-
Subtract
other
from this integer in place, and return a flag indicating if the operation caused an arithmetic overflow.other
is shiftedshift
digits to the left before being subtracted.Note
If the result indicates an overflow, thenself
becomes the twos’ complement of the absolute difference.Complexity
O(count)Declaration
Swift
public mutating func subtractReportingOverflow(_ b: BigUInt, shiftedBy shift: Int = 0) -> Bool
-
Subtract
other
from this integer, returning the difference and a flag indicating arithmetic overflow.other
is shiftedshift
digits to the left before being subtracted.Note
Ifoverflow
is true, then the result value is the twos’ complement of the absolute value of the difference.Complexity
O(count)Declaration
Swift
public func subtractingReportingOverflow(_ other: BigUInt, shiftedBy shift: Int) -> (partialValue: BigUInt, overflow: Bool)
-
Subtracts
other
fromself
, returning the result and a flag indicating arithmetic overflow.Note
When the operation overflows, thenpartialValue
is the twos’ complement of the absolute value of the difference.Complexity
O(count)Declaration
Swift
public func subtractingReportingOverflow(_ other: BigUInt) -> (partialValue: BigUInt, overflow: Bool)
-
Subtract
other
from this integer in place.other
is shiftedshift
digits to the left before being subtracted.Requires
self >= other * 2^shiftComplexity
O(count)Declaration
Swift
public mutating func subtract(_ other: BigUInt, shiftedBy shift: Int = 0)
-
Subtract
b
from this integer, and return the difference.b
is shiftedshift
digits to the left before being subtracted.Requires
self >= b * 2^shiftComplexity
O(count)Declaration
Swift
public func subtracting(_ other: BigUInt, shiftedBy shift: Int = 0) -> BigUInt
-
Decrement this integer by one.
Requires
!isZeroComplexity
O(count)Declaration
Swift
public mutating func decrement(shiftedBy shift: Int = 0)
-
Subtract
b
froma
and return the result.Requires
a >= bComplexity
O(a.count)Declaration
Swift
public static func - (a: BigUInt, b: BigUInt) -> BigUInt
-
Subtract
b
froma
and store the result ina
.Requires
a >= bComplexity
O(a.count)Declaration
Swift
public static func -= (a: inout BigUInt, b: BigUInt)
-
Undocumented
Declaration
Swift
public subscript(bitAt index: Int) -> Bool { get set }
-
The minimum number of bits required to represent this integer in binary.
Complexity
O(1)Declaration
Swift
public var bitWidth: Int { get }
Return Value
floor(log2(2 * self + 1))
-
The number of leading zero bits in the binary representation of this integer in base
2^(Word.bitWidth)
. This is useful when you need to normalize aBigUInt
such that the top bit of its most significant word is 1.Note
0 is considered to have zero leading zero bits.See also
widthComplexity
O(1)Declaration
Swift
public var leadingZeroBitCount: Int { get }
Return Value
A value in
0...(Word.bitWidth - 1)
. -
The number of trailing zero bits in the binary representation of this integer.
Note
0 is considered to have zero trailing zero bits.Complexity
O(count)Declaration
Swift
public var trailingZeroBitCount: Int { get }
Return Value
A value in
0...width
. -
Declaration
Swift
public struct Words : RandomAccessCollection
-
Declaration
Swift
public var words: Words { get }